Question

Find 10th term of an AP . 16,9,2​

Answer 1

Answer:

$\large\bf{Given:} \:$

$\mathrm{a_1= 16} \\ \mathrm{a_2= 9} \:$

$\mathrm{ d = a_2 - a_1 } \\ \implies \mathrm{9-16} \\ \implies \fbox{d = -7}$

$\large\bf{To \: Find : } \:$

$\mathrm { a_{10 }= ? } \:$

$\large\bf{Solution:} \:$

$\mathrm{ a_{10} = a + 9d } \\ \\ \implies \mathrm{ 16 + (9) -7} \\ \\ \implies \mathrm{16 - 63} \\ \\ \implies \fbox{ -47} \:$

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$\large\mathfrak\purple{Verified} \:$