Question

find 10th term of ap root 2,root8,root18....

Answer 1

We have AP √2, √8, √18 ,..........
which can be written as √2, 2√2, 3√2

So a = √2 and d = 2√2 - √2 = √2

So, a10 = a+9d
             = √2 + 9√2
             = 10√2
             = √200

Answer 2

this is ur answer.... I hope it will hlp u...