Question

find 10th term of given A.P -1,-6,-11,.... ​

Answer 1

Step-by-step explanation:

$a _n = 10$

$d = - 6 - ( - 1) = - 6 + 1 = - 5$

an =a+(n-1)d

Answer 2

Answer:

Given

a (first term) = -1

d (difference) = -6-(-1) = -6+1= -5

n = 10

$an = a + (n - 1)d \\ = - 1 + (10 - 1)( - 5) \\ = - 1 + 9( - 5) \\ = - 1 - 45 \\ = - 46$