Question

find 10th term of the a.p. 4, 9, 14​

Answer 1

Step-by-step explanation:

4, 9, 14........., 254

a = 4 and d = 5

tn = 254

a + (n - 1)d = 254

4 + (n - 1) × 5 = 254

5(n - 1) = 250

n - 1 = 50

n = 51

Hence, 10th term from the end is t42

t42 = a + (42 - 1)d

t42 = 4 + 41 × 5 = 209

Answer 2

Here, n= 10

a= 4

d = 9-4 = 5

t₁₀ = ?

Now, tn = a+(n-1)d

or, t₁₀ = 4+(10-1)×5

= 4+9×5

= 4+45

= 49 Ans.