Question

find 10th term of the series log a,log(a^2/b),log(a^3/b^2),........​

Answer 1

Answer:

This series is in AP so common difference=

$log( \frac{ {a}^{2} }{b} ) - log(a) = log( \frac{ {a}^{2} }{ab} ) = log( \frac{a}{b} )$

so 10th term =

$a_{10} = a + (n - 1)d = log(a) + (10 - 1) \times log( \frac{a}{b} ) =$

$log(a) + log( \frac{a}{b} ) {}^{9} = log( \frac{ {a}^{10} }{ {b}^{9} } )$

Ans.

Answer 2

Answer:

same as above solution. nice work