Find 11th term, 12th term, 20th term sum of 12,20,33 term
Answers
Answered by
0
Answer:
t
n
=
a
+
(
n
−
1
)
d
where:
t
n
=
any term in the arithmetic sequence
a
=
first term
n
=
term number/number of terms
d
=
common difference
To find the
12
t
h
term of the sequence, we first need to find
d
, the common difference. We can do this by subtracting
t
1
from
t
2
:
t
2
−
t
1
=
14
−
20
=
−
6
Now that you have the common difference, substitute all your known values into the formula to solve for
t
12
:
t
n
=
a
+
(
n
−
1
)
d
t
12
=
20
+
(
12
−
1
)
(
−
6
)
t
12
=
20
+
(
11
)
(
−
6
)
t
12
=
20
−
66
t
12
=
−
46
Answered by
0
Step-by-step explanation:
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