Question

Find 11th term of The AP 4,7,10.......

Answer 1

Step-by-step explanation:

let first term of AP is4 and d is 3 to find t11 Tn= a+(n-1)d

t11=4+(11-1)3

: 4+10*3

4+30

34

=11th term of an Appointment is 34

Answer 2

11th term of the given AP($a_{11}$) =  34

Step-by-step explanation:

The given AP are:

4, 7, 10, .......

Here, first term (a) = 4, common difference(d) = 7 - 4 = 3 and

the number of terms (n) = 11

To find, 11th term of the given AP($a_{11}$) = ?

We know that,

The nth term of the AP

$a_{n} =a+(n-1)d$

∴ 11th term of the given AP($a_{11}$)

= 4 + (11 - 1) × 3

= 4 + (11 - 1) × 3

= 4 + 10 × 3

= 4 + 30

= 34

∴  11th term of the given AP($a_{11}$) =  34

Thus, 11th term of the given AP($a_{11}$) =  34