Find 12 1 / 2 1. less than I6hr
Answers
Answered by
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Step-by-step explanation:
S
n
=(1+(
2
1
)
0
)+(1+(
2
−1)+
2
1
)+(1+2(
2
−1)+(
2
1
)
2
)+...+(1+(n−1)(
2
−1)+(
2
1
)
n−1
)
⇒S
n
=∑
r=0
n−1
1+r(
2
−1)+(
2
1
)
r
=
2
n
(2+(n−1)(
2
−1))+
1−
2
1
1−(
2
1
)
n
⇒S
n
=
2
n
(3+(n−1)
2
−n)+
(
2
)
n−1
(
2
−1)
(
2
)
n
−1
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