find
12(x+y)²-(x+y)-35
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Step-by-step explanation:
12(x+y)^2-(x+y)-35
=12(x^2+y^2+2xy)-(x+y)-35
=24xy+12x^2+12y^2-(x+y)-35
=12(x+y)(x+y)-(x+y)-35
=12(x+y)-35
=12x+12y-35
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