Question

find 125p³ - 8q³ if 5p-2q = 6 and pq= 4

Answer 1

Answer:

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Identity rule:

x^3 -y^3 = (x-y) ^3 +3xy (x-y)

Hence,

125p^3 -8q^3

=( 5p)^3 - ( 2q) ^3

= (5p-2q)^ 3 +3 5p ×2q (5p-2q)

= 6^3 + 3× 10 × 4 × 6

= 936

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