Question

Find............12th class students

Answer 1

∫ (5x³+2x^-5 -7x + 1/√x + 5/x) dx

We know that
•∫ xⁿ dx = xⁿ+¹/n+1 + C
•∫ 1/x dx = log x + C

Using the above formulas we get ...

∫ (5x³ + 2x^-5 -7x + 1/√x + 5/x) dx

= 5x⁴/4 -1/2x⁴ - 7x²/2 + 2√x + 5logx +C