Math, asked by Jamaltigauti6, 1 year ago

find 12th term from the end of ap -2,-4,-6-----100

Answers

Answered by mysticd
36
given -2,-4,-6,....,100 are inAP

first term = a= -2
common difference= d= a2- a1 = -4-(-2) = -4+2= -2

nth term = an =a +(n-1)d

here a= -2, d= -2, n=12

a12 = -2+(12-1) (-2)
= -2 +11(-2)
= -2-22
=-24
therefore
12th term in AP = a12= -24
Answered by Anonymous
8

Answer:

Given, -2, -5, -6,.... 100 are in A. P.

First term = a = -2

Common Difference = d = a2 - a1 = -4 -(-2) =

- 4 + 2= - 2

nth term = an = a + (n - 1)

here, a = -2, d = -2, n= 12

a12 = -2 + (12 - 1) (-2(

= -2 + 11 (-2)

= - 2 - 22

= - 24

Therefore, 12th term in A. P. = a12 = - 24

Step-by-step explanation:

@GENIUS

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