Question

Find 12th term of an AP 13,8,3,-2.......

Answer 1

here is the answer to that question...

Answer 2

$here \: first \: term \: a = 13 \\ difference \: \: \: d = - 5 \\ now \: 12th \: term \: \: \: \\ t12 = a + (n - 1) \times d \\ = 13 + (12 - 1) \times ( - 5) \\ = 13 + 11 \times ( - 5) \\ = 13 - 55 \\ = - 42 \\ this \: is \: your \: \: answer$
mark as brainliest answer.plz