Question

find 12th term of an AP -40, -50, -60,.....

Answer 1

Hey friend your answer....
here,
a=-40, d=-10
a12= a+(12-1)d
=-40+11×-10
=-40+(-110)
=-40-110
=-150

I hope it helps you
mark as brainlist plz

Answer 2

$\huge\red{Hello \: Friends}$

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Given A.P

-40,-50-60.....

Here ,

a = -40

t₁ = a = -40

t₂ = -50

∴ d = t₂ - t₁ = -50 - (-40) = -50+40 = -10

We have to find the 12th term of the given A.P

∴ n = 12

We know that,

tₙ = a + (n-1) d

Put the obtained values we get,

t₁₂ = -40 + (12-1) -10

t₁₂ = -40 + 11 x (-10)

t₁₂ = -40 - 110

t₁₂ = -150

$\boxed{t12 = - 150}$

$\huge{Thanks}$

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