Question

Find 12th term of an AP x-7,x-2,x+3......

Answer 1

Hey..here a=x-7
d=x-2-x+7
=5

So...an=a+(n-1)d
an=x-7+11*5
an=x+55-7
an=x+48
HOPE IT HELPS....!!!!!

Answer 2

$a = x - 7 \\ d =5 \\ tn = a + (n - 1)d \\ t12 = (x - 7) + 11 \times 5 \\ t12 = (x - 7 + 55) \\ t12 = x +48$
this is ur answer