Question

find 15625 and use it to find 156.25 + 1.5625
$\sqrt[?]{?}$
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Answer 1

Step-by-step explanation:

[1]

Find √15625 and use it to find the value of √156.25 + √1.5625.

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Firstly, we need to calculate the square root of 15625. By prime factorisation,

➝ √15625 = √(5 × 5 × 5 × 5 × 5 × 5)

➝ √15625 = 5 × 5 × 5

➝ √15625 = 125

Now, we have to find the value of √156.25 + √1.5625,

$\longmapsto\rm { \sqrt{156.25} + \sqrt{1.5625}}$

√156.25 and √1.5625 can be written as,

$\longmapsto\rm { \sqrt{\dfrac{15625}{100}} + \sqrt{\dfrac{15625}{10000} }}$

Now, as we know that √a/b is equivalent to √a/√b, so

$\longmapsto\rm { \dfrac{\sqrt{15625}}{\sqrt{100}}+ \dfrac{\sqrt{15625}}{\sqrt{10000} }}$

• Square root of 100 is 10.
• Square root of 10000 is 100.

$\longmapsto\rm { \dfrac{125}{10}+ \dfrac{125}{100}}$

Writing the fractions in the form of decimals.

$\longmapsto\rm { 12.5+ 1.25}$

Performing addition.

$\longmapsto\bf { 13.75}$

Therefore,

$\longmapsto\underline{\boxed{\bf{ \sqrt{156.25} + \sqrt{1.5625} = 13.75} }} \; \bigstar$

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[2]

Find square root of 2304 and 1764 and hence find the value of √0.2304 + √0.1764 and √0.2304 - √0.1764.

Finding the square root of 2304, by prime factorisation,

➝ √2304 = √(2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3)

➝ √2304 = 2 × 2 × 2 × 2 × 3

➝ √2304 = 48

Finding the square root of 1764, by prime factorisation,

➝ √1764 = √(2 × 2 × 3 × 3 × 7 × 7)

➝ √1764 = 2 × 3 × 7

➝ √1764 = 42

Now,

$\longmapsto\rm { \sqrt{0.2304} + \sqrt{0.1764}}$

√0.2304 and √0.1764 can be written as,

$\longmapsto\rm { \sqrt{\dfrac{2304}{10000}} + \sqrt{\dfrac{1764}{10000} }}$

Now, as we know that √a/b is equivalent to √a/√b, so

$\longmapsto\rm { \dfrac{\sqrt{2304}}{\sqrt{10000}}+ \dfrac{\sqrt{1764}}{\sqrt{10000} }}$

• Square root of 2304 is 48.
• Square root of 1764 is 42.
• Square root of 10000 is 100.

$\longmapsto\rm { \dfrac{48}{100}+ \dfrac{42}{100}}$

Writing the fractions in the form of decimals.

$\longmapsto\rm { 0.48+ 0.42}$

Performing addition.

$\longmapsto\bf { 0.9}$

Therefore,

$\longmapsto\underline{\boxed{\bf{\sqrt{0.2304} + \sqrt{0.1764} = 0.9} }} \; \bigstar$

Also,

$\longmapsto\bf { \sqrt{0.2304} - \sqrt{0.1764}}$

√0.2304 and √0.1764 can be written as,

$\longmapsto\rm { \sqrt{\dfrac{2304}{10000}} - \sqrt{\dfrac{1764}{10000} }}$

Now, as we know that √a/b is equivalent to √a/√b, so

$\longmapsto\rm { \dfrac{\sqrt{2304}}{\sqrt{10000}}- \dfrac{\sqrt{1764}}{\sqrt{10000} }}$

• Square root of 2304 is 48.
• Square root of 1764 is 42.
• Square root of 10000 is 100.

$\longmapsto\rm { \dfrac{48}{100}- \dfrac{42}{100}}$

Writing the fractions in the form of decimals.

$\longmapsto\rm { 0.48-0.42}$

Performing subtraction.

$\longmapsto\bf { 0.06}$

Therefore,

$\longmapsto\underline{\boxed{\bf{\sqrt{0.2304}- \sqrt{0.1764} = 0.06} }} \; \bigstar$

Answer 2

Answer:

biochemistry, an oxidoreductase is an enzyme that catalyzes the transfer of electrons from one molecule, the reductant, also called the electron donor, to another, the oxidant, also called the electron acceptor.

Step-by-step explanation:

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