Question

find 15th term a AP whose 2nd term is 11 and common difference is​

Answer 1

Answer:

15th term = a + 14d = 2+126=128

Step-by-step explanation:

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Answer 2

Answer:

a15=128

second term of an ap=11

common difference =9

d=a2-a1=9

d=11-a1=9

11-9=a1

2=a1

therefore a1=2

1st term =2

a15=a+14d

a15=2+14(9)

a15=2+126

a15=128

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