Question

find 15th term form end of the AP: 21,42,63,84... 585​

Answer 1

Answer:

reverse the ap

now,

a=585

d=-21

a15=a+14d

a15=585 +14×(-21)

a15=585-294

a15=291

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Answer 2

The 15th term from the end term of the arithmetic progression would be 291

Given

• AP: 21,42,63,84... 585

To find

• 15th term form end

solution

we are provided with an arithmetic progression and asked to find the 15 the term from the end term of the given arithmetic progression.

we know that arithmetic progression is a progression obtained by adding a fixed number known as common difference to a particular term known as the first term.

in the given arithmetic progression the first term would be 21 and the last term would be 585.

therefore,

a = 21

l = 585

common difference, d= 42-21

or, d = 21

the end term of the arithmetic progression is given by the standard equation,

l - (n-1)d

or, 585 - (15-1)21

or, 585 - 14×21

or, 585 - 294

or, 291

therefore, the 15th term from the end term of the arithmetic progression would be 291.

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