Question

find 16th term as AP, y first term
is 2 and common clifference
clifference is 5

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Answer 1

Answer:

it's given that,

a=2,d=5,n=16

an=a+(n-1)d

an=2+15×5

an=2+75

an=77

therefore 16th term of the ap is 77

Answer 2

Step-by-step explanation:

Given -

• First term of AP = 2
• Common difference (d) = 5

To Find -

• 16th term of AP

Solution -

As we know that :-

• $\mathsf{a_{n} = a + (n-1)d}$

Then,

$\mathsf{a_{16} = 2 + (16 - 1)5}$

$\mathsf{a_{16} = 2 + 75}$

$\mathsf{a_{16} = 77}$

Hence,

The 16th term of AP is 77.

Some other formulas -

1. $\mathsf{S = \dfrac{n}{2}[2a + (n - 1)d] }$
2. $\mathsf{S = \dfrac{n}{2} (a + l)}$
3. $\mathsf{b = \dfrac{a + c}{2} }$ (If a, b, c are in AP)