Math, asked by Anonymous, 8 months ago

FIND...................

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Answered by Anonymous
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\cos (   \dfrac{ x  }{ 2  }     )   \cos (   \dfrac{ x  }{  { 2  }^{ 2  }    }     )   \sin (   \dfrac{ x  }{  { 2  }^{ 2  }    }     )= \frac {sin(x)}{4}

\mathrm{Use\:the\:following\:identity}:\quad \cos \left(x\right)\sin \left(x\right)=\frac{\sin \left(2x\right)}{2}

=\frac{\sin \left(2\cdot \frac{x}{2^2}\right)}{2}\cos \left(\frac{x}{2}\right)

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

=\frac{\sin \left(2\cdot \frac{x}{2^2}\right)\cos \left(\frac{x}{2}\right)}{2}

\mathrm{Multiply\:}2\cdot \frac{x}{2^2}\::\quad \frac{x}{2}

=\frac{\sin \left(\frac{x}{2}\right)\cos \left(\frac{x}{2}\right)}{2}

\mathrm{Simplify}\:\sin \left(\frac{x}{2}\right)\cos \left(\frac{x}{2}\right):\quad \frac{\sin \left(2\cdot \frac{x}{2}\right)}{2}

=\frac{\frac{\sin \left(2\cdot \frac{x}{2}\right)}{2}}{2}

\frac{\sin \left(2\cdot \frac{x}{2}\right)}{2}=\frac{\sin \left(x\right)}{2}

=\frac{\frac{\sin \left(x\right)}{2}}{2}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{\sin \left(x\right)}{2\cdot \:2}

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4

=\frac{\sin \left(x\right)}{4}

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