Question

Find 19th term of( 2x^1/2-y^1/3)^20​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

760$xy^6$

Given,

$( 2x^\frac{1}{2} -y^\frac{1}{3} )^2^0$

we know that,

$(x+a)^n$ ⇒  $T_r_+_1 = ^nC_r x^n^-^ra^r$

Thus,

$T_1_9 = T_1_8_+_1 = ^2^0C_1_8 .(2x^\frac{1}{2})^2.(-y^\frac{1}{3})^1^8$

                    = 190 × 4 × x × $y^6$

                    =  760$xy^6$

Thus the 19th term is  760$xy^6$

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