find 1st and 2nd derivative of 3cos(logx)+4sin(logx)?
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hope this help u..........
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divyajyoti181ba:
ans of your question is
ans to thik hai
ok no problem
-1/x^2sin(logx)-7/x^2cos(logx)
okk
second differential
ok
hmmm
byee
byee
Answered by
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1st derivative :- -3sin(logx).1/x+4cos(logx).1/x
2nd derivative:- -3×1/x [cos(logx).1/x]+sin(logx)×3/x^2]+....... similarly 4 cos (logx) ka bhi kre
2nd derivative:- -3×1/x [cos(logx).1/x]+sin(logx)×3/x^2]+....... similarly 4 cos (logx) ka bhi kre
thanks
hii shivani
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