find
1st
derivatives
of y= xsinx
Answers
Answered by
0
Answer:
y' = xcosx + sinx
Step-by-step explanation:
y = x sinx
use product formula:
d/dx (u,v) = u (dv/dx) + v (du/dx)
so,
y' = x cosx + sinx.1
y' = x cosx + sinx
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