Math, asked by saurabhkumar841428, 3 months ago

find
1st
derivatives
of y= xsinx​

Answers

Answered by stayyaba177gmailcom
0

Answer:

y' = xcosx + sinx

Step-by-step explanation:

y = x sinx

use product formula:

d/dx (u,v) = u (dv/dx) + v (du/dx)

so,

y' = x cosx + sinx.1

y' = x cosx + sinx

Similar questions