Question

Findײ+2×+1 tell tell​

Answer 1

Step-by-step explanation:

${x}^{2} + 2x + 1 = 0 \\ {x}^{2} + 1x + 1x + 1 = 0 \\ x(x + 1) + 1(x + 1) = 0 \\ (x + 1)(x + 1) = 0 \\ x + 1 = 0 \: \: \: \: \: x + 1 = 0 \\ x = - 1 \: \: \: \: \: \: \: x = - 1$

Hope you get your answer

Answer 2

$\sf {x}^{2} + 2x + 1 \\ \\ \sf \: {x}^{2} + 1x + 1x + 1 \\ \\ \sf \: x(x + 1) + 1(x + 1) \\ \\ \sf (x + 1)(x + 1) = 0 \\ \\ \sf \:x+1=0 \:\: x+1=0 \\ \\ \sf \: \underline{\underline{x = ( - 1) \: \:x = ( - 1) }}$

The method i used here is splitting the middle term .

Here the middle term is 2x , which I splitter to 1x + 1x .

Then took the common out !

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