find (2+3i)+(-4+5i)-(9-3i).
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Answered by
1
Answer:
(2+3i)+(-4+5i)-(9-3i)
2 + 3i - 4 + 5i - 9 + 3i
2 - 4 - 9 + 3i + 5i + 3i
-11 + 11i
11i -11
11(i - 1)
Answered by
1
Answer:
The required simplification is 11 ( i - 1 ).
Step-by-step-explanation:
We have to simplify a complex number.
Now, we know that,
A number is complex if it is of form a + ib where, a, b are real numbers and i is imaginary unit; i² = - 1.
While adding or subtracting two complex numbers, real part ( a ) is added / subtracted to the real part and imaginary part ( bi ) is added / subtracted to the imaginary part.
Now,
( 2 + 3i ) + ( - 4 + 5i ) - ( 9 - 3i )
⇒ 2 + 3i - 4 + 5i - 9 + 3i
⇒ 2 - 4 - 9 + 3i + 3i + 5i
⇒ - 2 - 9 + 6i + 5i
⇒ - 11 + 11i
⇒ 11 ( - 1 + i )
⇒ 11 ( i - 1 )
∴ The required simplification is 11 ( i - 1 ).
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