Math, asked by anjaliaks93, 6 months ago

find (2+3i)+(-4+5i)-(9-3i).​

Answers

Answered by aakashkr470
1

Answer:

(2+3i)+(-4+5i)-(9-3i)

2 + 3i - 4 + 5i - 9 + 3i

2 - 4 - 9 + 3i + 5i + 3i

-11 + 11i

11i -11

11(i - 1)

Answered by varadad25
1

Answer:

The required simplification is 11 ( i - 1 ).

Step-by-step-explanation:

We have to simplify a complex number.

Now, we know that,

A number is complex if it is of form a + ib where, a, b are real numbers and i is imaginary unit; i² = - 1.

While adding or subtracting two complex numbers, real part ( a ) is added / subtracted to the real part and imaginary part ( bi ) is added / subtracted to the imaginary part.

Now,

( 2 + 3i ) + ( - 4 + 5i ) - ( 9 - 3i )

⇒ 2 + 3i - 4 + 5i - 9 + 3i

⇒ 2 - 4 - 9 + 3i + 3i + 5i

⇒ - 2 - 9 + 6i + 5i

⇒ - 11 + 11i

⇒ 11 ( - 1 + i )

11 ( i - 1 )

∴ The required simplification is 11 ( i - 1 ).

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