Find 2 consecutive even number such that sum of their squares is "1200"
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Let the numbers be x and x+1
x²+(x+1)²=1200
x²+x²+2x+2=1200
2x²+2x-1198=0
x²+x-599=0
x²+(x+1)²=1200
x²+x²+2x+2=1200
2x²+2x-1198=0
x²+x-599=0
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