Question

Find 2 consecutive even numbers such that half of the larger exceeds 1/4th of the smaller by 5.

Answer 1

Here it is..
Hope it helps

Answer 2

Answer:

Two consecutive numbers are 16 and 18.

Step-by-step explanation:

To find : 2 consecutive even numbers such that half of the larger exceeds 1/4th of the smaller by 5.

Solution :

Let the two consecutive even numbers are 2n , 2n+2

Half of the larger number $\frac{2n+2}{2}$

According to question,

$\frac{2n+2}{2}=\frac{2n}{4}+5$

$n+1=\frac{n}{2}+5$

$n-\frac{n}{2}=5-1$

$\frac{n}{2}=4$

$n=8$

So, The larger number 2n+2=2(8)+2=18

Smaller number 2n=2(8)=16

Therefore, Two consecutive numbers are 16 and 18.