Question

Find 2 consecutive integers such that two-fifth of the smaller exceeds two- ninth of the grater by 4​

Answer 1

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Find two consecutive odd integers such that two - fifth of the smaller exceeds two - ninth of the greater by 4.

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Let the smaller odd integer be x and greater odd integer be ( X + 2 )

$\frac{2}{5}$ of smaller exceedo $\frac{2}{5th}$ of greater odd by 4.

$=> \frac{2x}{5} = \frac{2}{5}(x + 2) + 4$

$=> \frac{2x}{5} = \frac{2x + 4 + 36}{9}$

$= > 18x \: = 5(2x + 40)$

$= > 18x \: = 10x \: + 200$

$=> 8x \: = 200$

$=> X \: = 25$

$=> X + 2 \: = 25 \: + 2 \\ \: \: \: \: \: \: \: \: \:\: \: \: = 27$

So, two consecutive odd integers are 25 and 27 .

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