Find 2 consecutive numbers whose squares differ by 25
Answers
Answered by
4
Hi mate
here is your answer
let the numbers be n,n+1
then
(n+1)²-n²= 25
n²+1+2n-n²=25
2n+1=25
2n=24
n=12
Hope it helps:)
Answered by
6
Answer:
12 and 13
Step-by-step explanation:
12² = 144
13² =169
144-169 = 25
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