Question

find 2 consecutive odd positive integers sum of whose square is 290​

Answer 1

Answer: 11 and 13

Step-by-step explanation:

let two consecutive odd no.s be x and x+2

According to question,

(x)^2 +(x+2)^2 = 290

2x^2+4x +4 = 290

x^2 +2x +2 = 145

x^2 + 2x -143 = 0

x^2 +13x -11x -143 = 0

(x-11)(x+13) = 0

So x = 11(-13 is excluded as we need only positive integers)

Therefore no.s are 11 and 13...