Question

Find 2 consecutive positive even integers such that their product is 1520

Answer 1

Answer:

Step-by-step explanation:

Let the number be x

The consecutive even integers will be in the form x,(x+2)

Their product is 1520

x(x+2)=1520

x^2+2x=1520

x^2+2x-1520=0

x^2+40x-38x-1520=0

x(x+40)-38(x+40)=0

(x+40)(x-38)=0

Case 1

x+40=0

x= -40

Case 2

x-38=0

x=38

Therefore the numbers could be (38,40) or (-40,-38)

Answer 2

a big mistake is there in above answer

in question there is given that the numbers are positive

therefore the numbers will be 38 and 40

and -38 and -40 are not the answers

plz mark this as brainleast answer