Question

find 2 consecutive positive integer whose sum of square is 840 std 10th

Answer 1

Step-by-step explanation:

Let the 4 consecutive positive integer as

2x+4x+6x+8x

2x+4x+6x+8x=840

20x=840

x= \frac{840}{20}

x=42

so the numbers are

2×42=84

4×42=168

6×42=252

8×42=336