Question

find 2 consecutive positive odd numbers the sum of whose square is 74​

Answer 1

Answer:

THE WAY OF EASIET METHOD YOUR ANSWER IS HERE MATE

let no. be x & x+2.

then, x^2 + (x+2)^2 =74

x^2 +x^2+4+2x=74

then,

2x^2 +2x+4-74=0

x^2+ 2x+2-37=0

x^2+2x-35=0

x^2+7x-5x-35=0

x(x+7)-5(x+7)=0

(x-5)(x+7)=0

x=5 & x=-7

Step-by-step explanation:

HOPE IT HELP U.

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Answer 2

Answer:

$\bold{The\ 2\ consecutive\ numbers\ are\ 5\ and\ 7.}$

Step-by-step explanation:

So let the 1st odd number be x, so the 2nd odd number will be x + 2.

Why x + 2? because if the odd number is 5 so the next odd number will be 7 or 5 + 2.

So putting the variables into equation...

By factorisation

x² + (x + 2)² = 74

x² + x² + 4x + 4 = 74

2x² + 4x + 4 = 74

2x² + 4x = 70

2x² + 4x -70 = 0

x² + 2x - 35 = 0

x² +7x -5x -35 = 0

x(x + 7) -5(x + 7) = 0

(x - 5) (x + 7) = 0

x = 5 and 7