find 2 natural numbers sum is 18 and product is 72
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Answered by
7
factorization of 72
72= 2×2×2×3×3
now,
the product of two natural number is =72
then, 12×2= 72
the sum of two natural number is = 18
the the number are 12+6= 18
so, the natural numbers are 12 and 6 .
72= 2×2×2×3×3
now,
the product of two natural number is =72
then, 12×2= 72
the sum of two natural number is = 18
the the number are 12+6= 18
so, the natural numbers are 12 and 6 .
Answered by
1
Answer:
Let the numbers be x and y
x+y=18
Xy=72
x=18-y
(18-y)y=72
18y-y²-72=0
y²-18y+72=0
a=1,b=-18,c=72
y= -b±√b²-4ac/2a
y= - -18±√-18²-4*1*72/2*1
y=18±√324-288/2
y=18±√36/2
y=18±6/2
so,y=18+6/2 or y=18-6/2
y=24/2 or y= 12/2
y=12 or y=6
substitute y=12 in first equation,
x+y=18
x+12=18
x=18-12
x=6
substitute y=6 in first equation,
x+y=18
x+6=18
x=18-6
x=12
ie, (x=6,y=12) (x=12,y=6)
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