Question

find 2 numbers, greater than 40 that have a HCF of 21 and a LCM of 1050

Answer 1

Answer:

Step-by-step explanation:

How do I find the 2 numbers when their LCM and HCF are given?

Product of Two Numbers X*Y = HCF * LCM. You see there are 4 variables Viz. X, Y, HCF and LCM. When HCF and LCM is given, we have 2 variables (X and Y) and only one equation i. e. X * Y = HCF * LCM.

Answer 2

Complete Question:-

Find the sum of 2 numbers, greater than 40 that have a HCF of 21 and a LCM of 1050.

The product of two numbers is 551.25.

Given:-

HCF of numbers = 21

LCM of numbers = 1050

To Find:-

The product of two numbers.

Solution:-

We can simply calculate the two numbers by using the following procedure.

As

HCF of numbers = 21

LCM of numbers = 1050

Let the two numbers be x and y respectively.

Product of numbers = LCM * HCF

$40x \times 40y = 21 \times 1050$

$40(x \times y) = 21 \times 1050$

$40(x \times y) = 22050$

$x \times y = \frac{22050}{40}$

$x \times y = 551.25$

Hence, the product of the two numbers is 551.25.

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