Question

find 2 numbers in the ratio 8:7such that when each is decreased by 12 and a half they are in the ratio 11:9

pls fast

Answer 1

Hey,
Let the numbers be X and y,
So, x/y=8/7
7x-8y=0-> first equation

Now, second equation,
x-12/y-12=11/19
19(x-12)=11(y-12)
19x-209=11y-132
19x-11y=77.

So, in the first equation,
7x-8y=0
x=8y/7.
Now, substitute X's value in equation second,
19(8y/7)-11y=77
152y/7-11y=77
75y/7=77
y=7*77/75
y=7.19.
And,x=8y/7
x=8*7.19/7
x=8.22.

Hope this helps you buddy!!
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