Question

Find 2 numbers such that one of them exceed the other by 13 and the sum is 77

Answer 1

Answer:

32 and 45

Step-by-step explanation:

A + B = 77

A= B+13

therefore

B+13+B = 77

2B = 77-13

2B = 64

B= 32.

and since A=B+13,  A= 45.

:)

Answer 2

1. we will take one as "x" and another as " x +13 "
2. than we will make up an equation like this -
3. x+x+13=77
4. 2x +13=77
5. 2x=77-13
6. 2x=64
7. x=64/2
8. x=32

• so , if one no. is 32 than another no. is exceed by 13 so , another no. 45.

• x=32
• x+13=45