Question

find 2 numbers which are exactly divisible by 12 and 16 lying between 200 and 300

Answer 1

Step-by-step explanation:

This is a problem of AP.

Here the first term between 200 and 300 divisible by 13 is 208. So the first term, a= 208 and the common difference between two consecutive terms is 13.

Last term between 200 and 300 which is divisible by 13 is 299. So the last term, Tn is 299.

We know that Tn = a+((n-1)*d) where d is the common difference and n is the number of elements.

So. Tn = 299 = 208+((n-1)*13)

299–208 = 91 = (n-1) *13

91/13 = 7 = n-1

Therefore, n= 7+1 = 8.

Therefore 8 numbers exist between 200 and 300 which are perfectly divisible by 13.