Question

Find 2 numbers whose sum is 23 and product is 120.

Answer 1

Answer:

Let the two numbers be x and y

According to question

x+y=23...(1)

x*y=120 ...(2)

now substitute value of x from eq(1) to eq.(2)

(23-y)*y=120

23y-y²=120

0=y²-23y+120

0=y²-15y-8y+120

0=y(y-15)-8(y-15)

0=(y-15)(y-8)

Either y=15 or 8....

x=23-15=8

or x=23-8=15

So the two numbers are 15 and 8...

Answer 2

Numbers are 8 and 15.

Given:

• The sum of two numbers is 23 and their product is 120.

To find:

• Find the numbers.

Solution:

Step 1:

Form the equations.

Let the numbers be x and y.

So, according to the question

$\bf x + y = 23 \: \: \: ...eq1$

and

$\bf xy = 120...eq2$

Step 2:

Find the value of x.

put value of y from eq2 in eq1.

From eq2

$y = \frac{120}{x}$

put this value in eq1

$x + \frac{120}{x} = 23$

$\implies \: {x}^{2} - 23x + 120 = 0$

$\implies \: {x}^{2} - 15x - 8x + 120 = 0$

$\implies \:x(x - 15) - 8(x - 15) = 0$

$\implies \:(x - 8)(x - 15) = 0$

$x=8$

or

$x=15$

Thus,

The values of x are 8 and 15.

Step 3:

Find the value of y.

If x=8, then

$8 + y = 23$

$\implies \: y = 23 - 8$

$\implies \: y = 15$

If x=15, then y= 8.

Thus,

Numbers are 8 and 15.

Learn more:

1) The sum of two numbers is 22 and the sum of their squares is 250. Find the numbers.

https://brainly.in/question/27417573

2)Find two numbers whose sum and product are 20 and 96 respectively

https://brainly.in/question/29481896

#SPJ3