Question

Find 2 (ordinate of P)+3 (abscissa of Q ) if P(-2 6) and Q(0 4) are two points on the cartesian plane.
PLEASE ANSWER ASAP I WILL MARK YOU AS BRAINLIEST
NO SPAMMING I WILL REPORT
NO COPYING OF QUESTION I WILL REPORT ​

Answer 1

Answer:

12

Step-by-step explanation:

For any point (x,y)

Abscissa = x coordinate

Ordinate = y coordinate

Given points are:

P(-2,6) and Q(0,4)

Thus ordinate of P)=6 and abscissa of Q =0

Hence

2 (ordinate of P)+3 (abscissa of Q )

=2*6+3*0

=12+0

=12