Question

find 20th term of AP whose first term is 10 and common difference is 3

Answer 1

Answer:

❥Answer

$given \: that \\ \\ a = 10 \: and \\ \\ d = 3 \\ \\ to \: find \\ \\ 20th \: term \\ \\ an = a + (n - 1)d \\ \\ a20 = 10 + (20 - 1)3 \\ \\ = 10 + 19 \times 3 \\ \\ = 10 + 57 = 67 \\ \\ therefore \: 20th \: tem \: of \: an \: ap \: is \: 67$

Answer 2

Given:

First term of AP = a = 10

Common difference of AP = d = 3

To Find:

The 20th term of the AP

Solution:

AP represents the set of numbers in which the difference between any two consecutive numbers is always the same.

Now, a = 10,d = 3, and n=20

Using the formula to calculate AP -

an = a + ( n-1)d

Substituting the values -

a20 = 10 + ( 20 - 1)3

Solving -

= 10 + 19 x 3

= 10 + 57

= 67

Answer: The 20th term of AP is 67.