Question

Find:23^-10/23^7.solve this plzzzz

Answer 1

$\frac{ {23}^{ - 10} }{ {23}^{7} } \\ \\ {23}^{ - 10 - 7} \\ \\ {23}^{ - 17} \\ \\ \frac{1}{ {23}^{17} }$




I hope this will help you




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Answer 2

HOLA!!

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REMEMBER A BASIC RULE

a^m ÷ a^n = a^(m-n)

Now in the question the bases are same. (that is 23)

APPLY IT

23^-10÷23^7 = 23^(-10-(7))

= 23^(-17)

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HOPE IT IS HELPFUL!!! :D