find 23 cube using column method
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Let x = 2 and
y = 3
(x)^(2) 2xy (y)^(2)
2^2 2×2×3 3^2
4 1 2 9
+1
5 2 9
So, (23)^(2) = 529
y = 3
(x)^(2) 2xy (y)^(2)
2^2 2×2×3 3^2
4 1 2 9
+1
5 2 9
So, (23)^(2) = 529
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helloworld7:
sorry or ans is correct but not method I wanted column method sorry
I have posted it with a picture to help you understand better.
again the method is correct but u gave me square but I want cube of 23
by column method
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