Question

find 25th term of A.P. 4,7,10,13....​

Answer 1

Answer:

$here, \\ 1st \: term,a = 4 \\ common \: \: difference \: = 7 - 4 = 3 \\ \therefore25th \: term, a_{25} = a + (n - 1)d \\ = 4 + (25 - 1)3 \\ = 4 + 24 \times 3 \\ = 4 + 72 \\ = 76. \\ \\ \therefore \: required \: 25th \: term \: = 76.$