Question

find 27÷(9÷3)

3
6
9
27
please ​

Answer 1

Answer:

9 is the answer. please mark me as brainlist.

Answer 2

Answer:

a(n)=(n-1)(-3), where n=the nth term of the sequence, n-1=the previous term, and where -3=a constant multiplier

PREMISES

1,-3,9,-27,81,

PATTERN

This sequence follows a geometric algorithm:

a(n)=(n-1)(-3), where n=the nth term of the sequence, n-1=the previous term, and where -3=a constant multiplier

PATTERN

(1) (-1/3)×-3=1

(2) 1×-3=-3

(3) -3×-3=9

(4) 9×-3=-27

(5) -27×-3=81

(6) 81×-3=-243

(7) -243×-3=729

(8) 729×-3=-2187

(9) -2187×-3=6561

(10) 6561×-3=-19683

(100) about 9×10^42(6561)(-3)=about -177147×10^42

and so forth

C.H.