find 27 x cube minus 27 x square Y + 9 x y square minus y cube if x is equal to 2 and Y is equal to 1
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Solution:
It is given that,
x = 2 , y = 1
27x³-27x²y+9xy²-y³
= (3x)³-3*(3x)²*y+3*(3x)*y-y³
= (3x-y)³
Now ,
substitute x = 2 , y = 1 we get
=(3×2 - 1)³
= (6 - 1)³
= 5³
= 125
Therefore,
Value of 27x³-27x²y+9xy²-y³
= 125
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