Question

find 27a^3+64b^3,if 3a+4b＝10 and ab ＝2​

Answer 1

$27a^3 + 64 b^ 3$

$(3a + 4b)(9a^2 + 16b ^2 - 12ab)$

$(3a + 4b){(3a + 4b) ^2 - 2 \times 3a \times 4b - 12b}$

given 3a+4b=10 and ab =2

putting the values in that equation

$10((10) ^2 - 24 \times 2 - 12 \times 2)$

10(100-48-24)

10(100-72)

10(28)

280

Answer 2

Answer:9940

Step-by-step explanation: