find 27a^3 +64b^3 , if 3a +4b = 10 and ab = 2
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given 3a+4b=10 and ab =2
putting the values in that equation
10((10) ^2 - 24 \times 2 - 12 \times 2)
10(100-48-24)
10(100-72)
10(28)
280
final result=280
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