Question

Find 27th term of Arithmetic progression in the following 12,9,6,3,0,

Answer 1

Solution:

A=12,n=27

d=9-12

=−3

Putting the values in below formula

a27 =a+(n−1)d

a27 = 12+(27−1)×−3

=9+(−78)

=9−130

=−69

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