Question

Find 27x³-64y³if 3x-4y=0and xy=12

who will send with step will be the brainliest​

Answer 1

0

Step-by-step explanation:

27x³-64y³ = (3x)³ - (4y)³

we know,

a³-b³= (a - b)³ + 3ab(a - b), use this here,

so, 27x³-64y³ = (3x)³ - (4y)³ = (3x - 4y)³ + 3(3x)(4y)(3x - 4y) = (3x - 4y)³ + 24xy(3x - 4y)

But A/C to question, (3x - 4y) = 0 and xy = 12

hence, 27x³ - 64y³ = (0)³ +24 × 12 × 0

= 0 + 0 = 0

Hope it helps you.. ❤️

Answer 2

Answer:

0

Step-by-step explanation:

=27$x^{3}$-64$y^{3}$

=$(3x)^{3}$-$(4y)^{3}$

$x^{3}-y^{3}=(x-y)(x^{2}+xy+y^{2})$

So Using Above Formula

=$(3x-4y)( (3x)^{2}+(3x)(4y)+(4y)^{2})$

Given That 3x-4y=0

=$(0)( (3x)^{2}+(3x)(4y)+(4y)^{2})$

So 0 Into Any Number Is 0

So Answer Is 0